Thursday Puzzle: Judkins’s Cattle

Another one from Dudeney:

“Hiram B. Judkins, a cattle-dealer of Texas, had five droves of animals, consisting of oxen, pigs, and sheep, with the same number of animals in each drove. One morning he sold all that he had to eight dealers. Each dealer bought the same number of animals, paying seventeen dollars for each ox, four dollars for each pig, and two dollars for each sheep; and Hiram received in all three hundred and one dollars. What is the greatest number of animals he could have had? And how many would there be of each kind?”


2 thoughts on “Thursday Puzzle: Judkins’s Cattle

  1. Unless it's required to have one of each animal in each drove (I couldn't tell from the question), then we have:

    5 oxen
    33 pigs
    42 sheep

    for 80 animals.

    BTW, nice picture of Shaun.

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